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BB84

@ BB84 @mander.xyz

Posts
11
Comments
92
Joined
2 yr. ago

  • ur dada so buff he falls significantly faster than g

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  • Re your first point: I was imagining doing the two experiments separately. But even if you do them at the same time, as long as you don’t put the two objects right on top of each other, the earth’s acceleration would still be slanted toward the ball, making the ball hit the ground very very slightly sooner.

    Re your second point: The object would be accelerating in the direction of earth. The 9.81m/s/s is with respect to an inertial reference frame (say the center of mass frame). The earth is also accelerating in the direction of the object at some acceleration with respect to the inertial reference frame.

  • ur dada so buff he falls significantly faster than g

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  • Nope. The argument only works if you conjured the bowling ball and feather out of thin air vacuum. https://lemmy.world/comment/13237315 discusses what happens when the objects were lifted off earth.

  • ur dada so buff he falls significantly faster than g

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  • I didn’t think about that! If the object was taken from earth then indeed the total acceleration between it and earth would be G M_total / r^2, regardless of the mass of the object.

  • ur dada so buff he falls significantly faster than g

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  • Okay how about now

  • ur dada so buff he falls significantly faster than g

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  • ur dada so buff he falls significantly faster than g

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  • fixed it sorry

  • ur dada so buff he falls significantly faster than g

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  • I meant cross-section area, not surface area. Sorry. Edited my comment above.

  • ur dada so buff he falls significantly faster than g

    Jump

  • If your bowling ball is twice as massive, the force between it and earth will be twice as strong. But the ball’s mass will also be twice as large, so the ball’s acceleration will remain the same. This is why g=9.81m/s^2 is the same for every object on earth.

    But the earth’s acceleration would not remain the same. The force doubles, but the mass of earth remains constant, so the acceleration of earth doubles.

  • ur dada so buff he falls significantly faster than g

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  • Here’s a problem for y’all: how heavy does an object have to be to fall 10% faster than g? Just give an approximate answer.

  • ur dada so buff he falls significantly faster than g

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  • Even in a perfect vacuum the bowling ball still falls faster. See my comment sibling to yours.

  • ur dada so buff he falls significantly faster than g

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  • Yes, the earth accelerates toward the ball faster than it does toward the feather.

  • ur dada so buff he falls significantly faster than g

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  • A feather has smaller cross-section area than a bowling ball. But drag acceleration is proportional to the cross-section area divided by the mass (and this quantity is indeed smaller for the bowling ball).

    Anyway the hypothetical scenario in this meme is a perfect vacuum. Check my other comments to see why it still works.

  • ur dada so buff he falls significantly faster than g

    Jump

  • When the earth pulls on an object with some F newtons of force, the object is also pulling on the earth with the same force. It’s just that the earth is so massive that its acceleration F/m will be tiny. Tiny is not zero though, so the earth is still accelerating toward the object. The heavier the object, the faster earth accelerates toward it.

    Both the bowling ball and the feather accelerates toward earth at the same g=9.81m/s^2, but the earth accelerates toward the bowling ball faster than it does toward the feather.